How to play a list that skips the numbers according to the number entered

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#1 by (4 votes)
#2 by (2 votes)

1

Preferably something that explains the answer below (without the spaces)

0

1

4

9

16

python-3.x

asked by anonymous 14.10.2017 / 17:00

2 answers

2

If you want something that manages this result you showed in the question, just do this:

i = 0
lista=[]

while i < 5:
   lista.append((i ** 2)) 
   i += 1

Output:

[0, 1, 4, 9, 16]

and so on.

14.10.2017 / 17:17

score 4 · Accepted Answer

4

You can use list comprehension for this much more idiomatic question:

[ i**2 for i in range(5) ]

14.10.2017 / 19:33