I'm having trouble inserting a variable into an array ... I did a search here and did not find any similar question that could help me solve this, so I'm creating this one.
The error: Parse error: syntax error, unexpected T_VARIABLE points to line 26
On line 26 I have this:
var $users = array('user1' => $senha);
The variable $ password that is causing the error ... if I put a string any functions without error.
The Parse error: syntax error, unexpected T_VARIABLE means that PHP was not expecting a variable at any given time.
This error can occur in some situations, but your question includes some special cases.
The most common problem is the absence of a comma point in the previous line. The interpreter in this case informed the error in the next line that occurs, and not in the line where the semicolon is missing:
<?php
$var = 1
$var2 = 3;
Returns the error:
Parse error: syntax error, unexpected '$ var2' (T_VARIABLE) in path / file on line 4
Another problem is in the definition of the word var before the variable in a context outside of a class.
This keyword was used in PHP 4 to define class properties, and currently exists only to maintain comparability with old codes.
In recent versions, it is a synonym for public .
Simply remove var when defining variables in PHP.
$users = array('user1' => $senha);
Now, if you are setting $user to a class property, the problem is that it is not possible to define dynamic values directly in the class definition (basically variables or functions), such as be noted in the documentation .
<?php
class SimpleClass
{
// declaração de propriedades invalidas:
// ...
public $var5 = $myVar;
}
This explains why var $users = array('user1' => 'Blabla'); works.
Recommendations
See if the line above the one entered in the error ends with ;
Do not use var in PHP 5 onwards, prefer private , protected or public .
If you need to define dynamic values in the class property, you can do this by the constructor method:
<?php
class SimpleClass
{
public $users = array();
public function __construct($senha){
$this->users = array('user1' => $senha);
// ...
}
}