I have the following regex:
preg_match_all('/([0-9]+[\.]*[0-9]*[\,.]*[0-9]*)/', $string, $matches)
If I get a string:
1 - João da Silva number 123456 with the value of R $: 6,298.65
I have a return:
array (size=27)
0 => string '1' (length=1)
1 => string '123456' (length=5)
2 => string '6.298,65' (length=8)
However, I would like to return only the actual value: 6,298.65
The problem is that you are leaving everything as "optional" ( * ).
The REGEX that can help you is:
~R\$:[\t ]*(\d{1,3}\.?)+(,\d{2})?~
I think you're looking for the default numero.numero,numero , I'd make a regex like this:
/\d+\.\d+,\d+/
\d is a shortHand that looks for numbers, is the same as the set [0-9]
+ is a quantifier that searches for 1 or more elements, is the same as {1,}
\. will search for a string because I used \ .
If you need the text to start with you R$: you should add R\$: at the beginning of the regex, you must use Scape\ because $ is a border that looks at the end of the text. >