I am trying to do if in case the person type 12 in any part of the text he enters the if but he is not entering
if ($_POST['mensagem'] !="%12%"){
echo"vc digitou 12";
}
Problem with $ _POST and IF
1
asked by anonymous 23.03.2018 / 00:30
1 answer
10
To know if one text is contained in another, use strpos .
if ( strpos( $_POST['mensagem'] , '12' ) !== false ){
echo 'vc digitou 12';
}
Important: Note the use of !== false , because if string is at the beginning, using only != will go wrong, because strpos will be zero, indicating that there is a 12 , but at the beginning of the string , since the count starts at the zero position.
If you want the reverse behavior:
if ( strpos( $_POST['mensagem'] , '12' ) === false ){
echo 'vc NAO digitou 12';
}
Use === for the same reason explained above.
Note that there are other functions to find substrings , but the manual itself recommends strpos for these cases, due to the significant performance difference.
More details in the manual:
Recommended reading on% difference from% to === to !== and == :
23.03.2018 / 00:44