My goal is to count how many elements of a given list correspond to a condition. For that, I made the following lines of code:
cont = 0
seq = []
max = 10
for x in seq if x == max:
cont = cont+1
However, I get syntax error in if x == max . How can I resolve this?
Hello. The syntax used by the master in his code is incorrect based on the language patterns, and Python, a block is always delimited by two '': colon followed by a:
user preference tab wrapping with 4 pre-defined spaces in the IDE
The most accessible syntax based on your question would be as follows.
cont = 0
seq = [0 , 5, 6, 7, 8, 9, 6, 10, 10, 25]
max = 10
for x in seq:
if x == max:
cont = cont+1
op = int(input("DESEJA VERIFICAR O RESULTADO? DIGITE 1 PARA VISUALIZAR OU OUTRO VALOR PARA SAIR " ))
if op == 1:
print("FORAM ENCONTRADOS %i valores" %(cont))
else:
print()
Note that I modified the original program and applied the display option, so the user could choose to see how many values are between the conformities or exit the program.
if can not be on the same line as for .
cont = 0
seq = []
max = 10
for x in seq:
if x == max:
cont = cont + 1
print(cont)
See running on ideone . And at Coding Ground . Also put it on GitHub for future reference .
To count the elements of a list that satisfy a given condition, given the title of the question ("list comprehension") you can do:
seq = [1,3,4,21,10,30,10,24]
max = 10
cont = len([x for x in seq if x == max]) # 2
Note that for this specific purpose (since the condition is equality, == ) suffice and I advise you to do:
cont = seq.count(max)
PS: This occurs because you have if on the same line as for , not correct syntax for a list comprehension