I have more or less the following code implemented in C #:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
namespace Teste
{
public class Program
{
public static void Main(string[] args)
{
Console.WriteLine(0134.ToString());
}
}
}
But it does not display int 0134 all:
O 0 on the left is not appearing.
0134.ToString("D4");
In this way somehow you must pass as many elements as there are in the integer, if for example your integer is 00134 , the first element would not appear, you would need to change D4 to D5
Format: .ToString("D[n]") or .ToString("d[n]")
n is optional and means the size of string , and if the number does not reach the set size the string is completed with 0 on the left.
Ex:
123.ToString("D"); //-> Saída: "123"
123.ToString("D1"); //-> Saída: "123"
123.ToString("D2"); //-> Saída: "123"
123.ToString("D3"); //-> Saída: "123"
123.ToString("D4"); //-> Saída: "0123"
123.ToString("D5"); //-> Saída: "00123"
Source | MSDN
There is also the explicit form, which is more flexible and can do the same thing as the abbreviated form.
Ex:
123.ToString("00000"); //-> Saída: "00123"
123.ToString("000"); //-> Saída: "123"
123.ToString("0-0-0"); //-> Saída: "1-2-3";
123.ToString("0-0"); //-> Saída: "12-0";
Source | MSDN