Create image blob in PHP

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Create image blob in PHP

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How can I create a blob of an image in PHP and return to JS? I've already tried using file_get_contents() returning to jQuery and creating an objectURL but it obviously did not work.

php javascript

asked by anonymous 27.08.2016 / 14:55

1 answer

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score 0 · Answer 1

If you are converting the URL image to your regular version you may be including the "data:image/*;base64," header, it will end up preventing the image from being read, as well as being unnecessary. If so, just do something like this before decoding the base64 string: substr(imageURL, strpos(imageURL, ',') +1) , and maybe it can be solved.

Another possible error: You may be receiving the content of this image in the wrong way. URL.createObjectURL requires the first argument as an instance of Blob . Maybe the response type of your XHR (if you're using) is not "blob" , so just do something like (xhr.responseType = "blob") , before xhr.send(); , hence: URL.createObjectURL(xhr.response) .

Answering the question, try:

(PHP)

<?php

/* responde o client-side com o conteúdo binário da imagem */
echo file_get_contents("image.png");

(JavaScript (% of jQuery% does not provide jqXHR ))

var xhr = new XMLHttpRequest;
xhr.open('GET', "*.php", true);
/* define a resposta do tipo "blob" */
xhr.responseType = "blob";

xhr.onreadystatechange = function() {
    if (xhr.readyState === 4) {
        if (xhr.status === 200) {
            var file = URL.createObjectURL(xhr.response);

        } else /* erro de requisição */ ;
    }
}; xhr.send();