IF, ELIF and ELSE

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I'm taking my first steps in Python, and I had a question in the if / else statement, trying to solve the following exercise:

"Based on input data for a person's height and gender, construct an algorithm that calculates their ideal weight using the following formulas:

For men: (72.7 * h) - 58

For women: (62.1 * h) - 44.7 (h = height)

Ask the person's weight and tell them if they are in, above or below weight.

This was the logic I used: 

def main():

altura = float(input("Digite a altura do paciente: "))
sexo = input("Digite o sexo do paciente, H(Masculino) ou F(Feminino): ")


altura
if sexo == H or sexo == h:
    peso = (72.7 * altura) - 58
    print ("O peso ideal do paciente é: ",peso)

    elif sexo == F or sexo == f:
        peso = (62.1 * altura) - 44.7
        print ("O peso ideal da paciente é: ",peso)

        else:
            print ("Sexo inválido")


pesopaciente = input("Digite o seu peso: ")

if pesopaciente < peso:
    print("Você está abaixo do peso ideal.")

    elif pesopaciente > peso:
        print("Você está acima do peso ideal.")

        else:
        print("Você está na média de peso.")


main()

However, it returns the following error:

  

Traceback (most recent call last):

     

File "python", line 12

     

elif sex == F or sex == f:

     

^

     

SyntaxError: invalid syntax

Could you help me?

Thank you!

    
asked by anonymous 04.10.2016 / 19:54

2 answers

2

When you put sexo == H it understands that you are referring to the H variable. Enclose in quotation marks, like this: sexo == "H" or sexo == "h"

Furthermore the indentation is all wrong. The content of the main function is not indented, and elif and else must be in the same column as if .

Read this article:

Indentation in python

I do not have python 3 with me to test, only 2.7 ... but I believe this code will work: 

def main():
    altura = float(input("Digite a altura do paciente: "))
    sexo = input("Digite o sexo do paciente, H(Masculino) ou F(Feminino): ")

    if sexo == "H" or sexo == "h":
        peso = (72.7 * altura) - 58
        print ("O peso ideal do paciente é: ",peso)
    elif sexo == "F" or sexo == "f":
        peso = (62.1 * altura) - 44.7
        print ("O peso ideal da paciente é: ",peso)
    else:
        print ("Sexo inválido")

    pesopaciente = input("Digite o seu peso: ")

    if pesopaciente < peso:
        print("Você está abaixo do peso ideal.")
    elif pesopaciente > peso:
        print("Você está acima do peso ideal.")
    else:
        print("Você está na média de peso.")

main()
    
04.10.2016 / 20:15
-1

In addition to correcting the indentation and quotation marks, you should use the raw_input() function rather than the simple input() function. When using the input() function, the user should write "h" (with quotation marks) so that the program recognizes the character as a string.

The input() function recognizes the user input as being Python code. That is, by entering only h (without quotes), python would try to evaluate this variable, which does not exist in your program.

The raw_input () function, in turn, returns the string of ASCII characters entered by the user before pressing ENTER, this string being interpreted as a string.

    
04.10.2016 / 20:36
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