I need a help with a program that reads a file and responds in which line it contains a string inside it.
Example
I have a .txt file and inside it I have 5 lines:
File.txt:
arroz
batata
feijão
carne
laranja
I need the program to return me, for example, if I look for orange line 5, if I look for potato, line 2.
You can do the following:
with open('Arquivo.txt') as f:
for l_num, l in enumerate(f, 1): # percorrer linhas e enumera-las a partir de 1
if 'laranja' in l: # ver se palavra esta na linha
print('laranja foi encontrada na linha', l_num)
break
else: # caso não haja break
print('nao foi encontrada a palavra')
Using a function:
def get_line(word):
with open('Arquivo.txt') as f:
for l_num, l in enumerate(f, 1): # percorrer linhas e enumera-las a partir de 1
if word in l: # ver se palavra esta na linha
return l_num
return False # não foi encontrada
print(get_line('laranja')) # 5
print(get_line('feijão')) # 3
print(get_line('banana')) # False
If you want to verify that the line is exactly the same as the word you can change the condition to strip() ):
...
if word == l.strip(): # retirar quebra de linha
...
One way to do it in a slightly longer version:
#!/usr/bin/env python3
arquivo = 'arquivo.txt'
pesquisa = 'batata'
achei = False
with open(arquivo,'r') as f:
linha = 1
for texto in f:
if pesquisa == texto.strip():
achei = True
break
linha+=1
f.close()
if achei:
print('Encontrado "{}" na linha {}'.format(pesquisa, linha))
else:
print('Não encontrei "{}"'.format(pesquisa))
It reads the file line by line, searching for the text placed in search , this version is not the fastest but is more didactic.
#!/usr/bin/env python3
import sys
lines = open("arquivo.txt").readlines()
for i in range(0, len(lines)):
if sys.argv[1] in lines[i].strip():
print("%s na linha %d" % (lines[i].strip(), i + 1))
break
How to use:
$ ./teste.py lara
laranja na linha 4
If you want to change the test of the fragment by an exact test, replace "in lines ..." with "== lines ...".