Using Struct in C language exercise

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Using Struct in C language exercise

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#2 by (0 votes)
#3 by (-2 votes)

2

/ * Write an algorithm that reads data from "N" people (name, sex, age and health) and whether or not you are fit to perform compulsory military service. Enter the totals. * /

#include <stdio.h>
#include <stdlib.h>

struct Pessoa
{
    char nome[30];
    char sexo[1]; // M = Masculino e F = Feminino
    int idade;
    char saude[5];
};

main()
{

    int quant; // Quantidade de pessoas

    printf("Digite a quantidade de pessoas: ");
    scanf("%d", &quant);

    struct Pessoa candidato[quant];

    int i;

    for(i = 0; i < quant; i++)
    {
        printf("\nNome: ");
        fgets(candidato[i].nome,30,stdin);

        printf("\nSexo: ");
        fgets(candidato[i].sexo,1,stdin);

        printf("\nIdade: ");
        scanf(" %d", &candidato[i].idade);

        printf("\nSaude: ");
        fgets(candidato[i].saude,5,stdin);

        if(candidato[i].idade >= 18 && candidato[i].saude == "boa")
        {
            printf("O %s, sexo %s com idade %d e com saude %s esta apto ao servico militar. \n\n",
                   candidato[i].nome, candidato[i].sexo, candidato[i].idade, candidato[i].saude);
        }
        printf("\n\n");

    } // fim do for

} // fim função main()

But when I use fflush it shows "Name: Sex" (on the same line) how do I solve this?

c

asked by anonymous 15.03.2014 / 15:07

3 answers

0

Try (note the dynamic memory allocation):

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Pessoa {
    char nome[31];
    char sexo; // M = Masculino e F = Feminino
    int idade;
    char saude[6];
};

main() {
    struct Pessoa *candidato;
    int quant; // Quantidade de pessoas
    int i;
    printf("Digite a quantidade de pessoas: ");
    scanf("%d", &quant);
    candidato = (struct Pessoa *) malloc(quant*sizeof(Pessoa));
    for(i=0; i<quant; i++)  {
        printf("\nNome: ");
        fgets(candidato[i].nome,30,stdin);
        printf("\nSexo: ");
        scanf("%c",&candidato[i].sexo);
        printf("\nIdade: ");
        scanf(" %d", &candidato[i].idade);
        printf("\nSaude: ");
        fgets(candidato[i].saude,5,stdin);
        if(candidato[i].idade >= 18 && strcmp(candidato[i].saude, "boa") == 0) {
            printf("O %s, sexo %c com idade %d e com saude %s esta apto ao servico militar. \n\n",
                   candidato[i].nome, candidato[i].sexo, candidato[i].idade, candidato[i].saude);
        }
        printf("\n\n");
    } // fim do for
    free(candidato);
} // fim função main()

18.03.2014 / 04:46

-2

One option would be to use fgets instead of scanf :

    scanf(" %[^\n]s",&candidato[i].nome);

15.05.2015 / 19:46

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score 4 · Accepted Answer

The struct definition gets better out of the function.

char sexo[0] has space for zero letters. To keep "M" (or "F") and terminator accurate for at least 2 characters

for(i = 0; i <= quant; i++) will run the loop one more than necessary

After fetching the age with scanf() , an ENTER is "hung" in the input stream. The next read takes this ENTER and returns an empty string

Where is the rest of the program? ???

The gets() function should not be used. Because it was so badly thought this function was not part of C Standard in the last version (few compilers use the latest version of Standard)

Good luck and have fun !