How to read a row of integers and store in a dynamic-sized vector?
I currently read the string as a string (though the input is only integer) using gets, the only way that worked.
The code looks like this:
type def struct{char entradas[50];} Processo
int main(){[...] Processo processos; gets(processo[i].entradas); }
And it works, but I need to be variable this size of entries []
You might as well continue with what you are doing and create a vector of virtually unlimited size, eg% w / w
Or create a buffer and go load the items partially:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void* vetgen(void *vetor,int newsize,int size){
void *newarr=malloc(newsize);
memcpy(newarr, vetor,size);
free(vetor);
return newarr;
}
int main(){
int* vetor,i,aux=1;
vetor=malloc(sizeof(int)*256);
do{
scanf("%d ",vetor+i);
i++;
if(i%256==0){
vetor = (int*) vetgen(vetor,i*(aux+1),i*aux);
aux++;
}
}while(!feof(stdin));
}
This code is just to give you an idea, to read entries in C even from entrada[500000]; recommend using stdin and fgets()