I'm using this expression to not let the user type a dot before any number and limiting 2 boxes after the comma, but I also needed to limit 5 boxes before the comma, the way I am I can insert as many numbers as I can before the comma . Does anyone know how I can do this? I'm catching up here.
My expression: "([0-9]+(\.)?([0-9]?[0-9]?))"
The same way you did to limit it later:
"([0-9][0-9]?[0-9]?[0-9]?[0-9]?(\.)?([0-9]?[0-9]?))"
That is, the former is required, and the following 4 are optional. However, I have some suggestions for improving this regex:
Use the keys to choose the number of times an element will repeat itself. exp{n} means that the expression must occur exactly n times. exp{a,b} means that it needs to occur at least a and at most b times:
"([0-9]{1,5}(\.)?([0-9]{0,2}))"
If these groups are not capture, I suggest removing them, as this unnecessarily complicates regex:
"[0-9]{1,5}\.?[0-9]{0,2}"
This is still possible to have a point with no digits in front, or no point and two digits too long. Connect the dot to the digits, and require at least 1 digit if the dot is present:
"[0-9]{1,5}(\.[0-9]{1,2})?"
You can use \d (escaped, \d ) to represent a digit instead of the [0-9] range:
"\d{1,5}(\.\d{1,2})?"
If you want to avoid zeros on the left, separate the case from 0 with the case of [1-9] followed by 0 to 4 digits:
"(0|([1-9]\d{0,4}))(\.\d{1,2})?"
I suppose it can satisfy you:
/^(\d{1,5})?(\.\d{1,2})?$/
Here dry an example in% with% of validation:
$('input').keyup(function(e){
var val = this.value;
var test = /^(\d{1,5})?(\.\d{1,2})?$/
if(test.test(val)){
$("p").html("Válido.")
}else{
$("p").html("Inválido.")
}
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script><inputtype="text" value="12345.67"/><br>
<p></p>