I have found the following using a Python REPL:
3 == 3 > 2
=> True
At first I thought it might be something related to operator precedence, however:
3 == (3 > 2)
=> False
(3 == 3) > 2
=> False
How does this work then? Is it simply returning the result of 3 == 3 and ignoring the > 2 part? Or does it 3 == 3 AND 3 > 2 ? Or something else? I know very little about Python.
In fact, your last interpretation is correct. A common idiom in programming is to test whether a number belongs to a range, i.e. if it is greater (or equal) to a and less (or equal) to b . In C for example, we would do this:
if ( a < x && x < b) {
While in mathematics we simply write:
a < x < b
Python decided to support this second form, interpreting something written as:
if a < x < b:
How to:
if a < x and x < b:
For this reason, three or more string comparison operators are even interpreted as pairs joined with "E". So it's equivalent to writing:
if 3 == 3 > 2:
E:
if 3 == 3 and 3 > 2:
Resulting, as you noticed, in True .
Note: equivalent as long as the operands have no side effects ; a() == b() > c() only evaluates functions once, while a() == b() and b() > c() evaluates b twice.