Read table in Lua through C ++

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2

I have a table in Lua like this: 

myTable={
  one = {a=1, b=2, c=3},
  two = {a=4, b=2, c=1}
}

The file has already been loaded, how do I read the table data through C ++?

    
asked by anonymous 21.03.2015 / 08:06

1 answer

4

I found the Lua user list this code: 

#include <stdio.h>
extern "C" {
    #include "lua/lua.h"
    #include "lua/lualib.h"
    #include "lua/lauxlib.h"
}
// In Lua 5.0 reference manual is a table traversal example at page 29.
void PrintTable(lua_State *L) {
    lua_pushnil(L);
    while(lua_next(L, -2) != 0) {
        if(lua_isstring(L, -1))
          printf("%s = %s\n", lua_tostring(L, -2), lua_tostring(L, -1));
        else if(lua_isnumber(L, -1))
          printf("%s = %d\n", lua_tostring(L, -2), lua_tonumber(L, -1));
        else if(lua_istable(L, -1))
          PrintTable(L);
        lua_pop(L, 1);
    }
}

void main() {
    lua_State *L = lua_open();
    // Load file.
    if(luaL_loadfile(L, "seuCodigo.lua") || lua_pcall(L, 0, 0, 0)) {
        printf("Cannot run file\n");
        return;
    }
    // Print table contents.
    lua_getglobal(L, "myTable");
    PrintTable(L);
    // Print specific field.
    lua_getglobal(L, "myTable");
    lua_pushstring(L, "one");
    lua_gettable(L, -2);
    if(lua_isstring(L, -1))
        printf("\myTable.one = %s\n", lua_tostring(L, -1));
    lua_close(L);
}

You probably have to adapt to what you want but it is already a start considering that you had nothing done.

21.03.2015 / 08:48
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