Get names of a form in a php page and put it in a select type list on another php page [closed]

As you are using mysql (I advise you to study mysqli or PDO ), first select it from the cadastrar_loja table on the page cadastrar_documento.php :

$consulta = mysql_query("SELECT id,nome FROM cadastrar_loja ORDER BY nome DESC");

Then do <select> :

<select class="form-control" name="txtNomeLoja" >
    <?php while ($dados = mysql_fetch_array($consulta)) { ?>
      <option value=<?=$dados['id']?>> <?=$dados['nome']?> </option>
    <?php } ?>
</select>   

The value of <select> will receive the id of the store and for the user the nome of the store will be displayed.

Good afternoon, Túlio,

Another, and safer, option would be to use the PDO. It would look something like this:

<?php
try {
    $conn = new PDO('mysql:host=enderecodohost;dbname=nomedodb', $usuario, $senha);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
    echo 'ERROR: ' . $e->getMessage();
}

$stmt = $conn->prepare('SELECT id, nome FROM lojas ORDER BY nome ASC');
$stmt->execute();
$data = $stmt->fetchAll(PDO::FETCH_ASSOC);

?>
<select name="lojas">
    <?php foreach($data as $row) { ?>
        <option value="<?= $row['id']; ?>"><?= $row['nome']; ?></option>
    <?php }?>
</select>

You can still pass PDO :: FETCH_CLASS as parameter of the fetchAll () function, and work with OO. In this case your query return would be objects instead of arrays.

I hope I have helped!