I have a vector with four elements that are numbers represented in hexadecimal form.
What I need to do is concatenate these four elements (I think this is not the right word but I have not found a better one)?
For example:
int v[4]={0xA, 0xBB, 0x4B, 0x18};
I need a result that looks similar to:
int resultado=0xABB4B18;
It has a form to print only and one that actually calculates correctly and prints:
#include <stdio.h>
int main(void) {
int v[4] = {0x0A, 0xBB, 0x4B, 0x18};
for (int i = 0; i < 4; i++) {
printf("%02X", v[i]);
}
return 0;
}
See running on ideone .
#include <stdio.h>
int main(void) {
int v[4] = {0x0A, 0xBB, 0x4B, 0x18};
int resultado = 0;
for (int i = 0; i < 4; i++) {
resultado *= 256;
resultado += v[i];
}
printf("%08X", resultado);
return 0;
}
See working on ideone .
Well, if you multiply a HEXA number by 100 in HEXA, you "move" to the right.
For example:
in DECIMAL - > 13 * 100 = 1300
in HEXADEC - > 0x13 * 0x100 = 0x1300
Try applying this concept to "concatenate" the HEXA values.
Another example:
If A = 0xE3, B = 0x4C, then A * 0x100 + B = 0xE34C.