Calculation to determine if triangle is rectangle does not give expected result

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Calculation to determine if triangle is rectangle does not give expected result

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#1 by (4 votes)
#2 by (2 votes)

2

The program I created receives three integer values, calculates the values inside% cos_de% and if the condition is correct it should show the SIM (the triangle is a rectangle), and if the condition is not satisfied, it should show NO.

By typing values 3, 4 and 5 the output must be YES, typing 3, 3 and 4, the output should be NAO, but this is giving YES in all cases.

Follow the code:

#include <stdio.h>
#include <math.h>

int main (void)

{
    int hip, cat1, cat2;

    scanf("%d", &cat1);

    scanf("%d", &cat2);

    scanf("%d", &hip);

    if (hip = pow(cat1,2) + pow(cat2,2))
    {
        printf("SIM");
    }

    else
    {
        printf("NAO");
    }


    return 0;
}

How to solve?

c

asked by anonymous 04.04.2015 / 01:30

2 answers

2

Previous version variant (@bigown)

#include <stdio.h>
#include <math.h>
#define ERROMAX 0.0001

int main (void) {
    float hip, cat1, cat2;
    scanf("%f", &cat1);
    scanf("%f", &cat2);
    scanf("%f", &hip);
    if (fabsf(hip - sqrt(pow(cat1,2) + pow(cat2,2))) < ERROMAX ) {
        printf("SIM\n");
    } else {
        printf("NAO\n");
    }
    return 0;
}

so as to give

1 1 1 -> não 

3 4 5 -> sim

04.04.2015 / 13:10

How to get the element id from its class Pass each result of an array to a variable

score 4 · Accepted Answer

There are two problems:

You used = and not == , to compare is the second, you assigned a new value to the hypotenuse.

You did not use the square root, so the formula is wrong. But there is a better formula.

See:

#include <stdio.h>
#include <math.h>

int main (void) {
    int hip, cat1, cat2;
    scanf("%d", &cat1);
    scanf("%d", &cat2);
    scanf("%d", &hip);
    if (hip*hip == cat1*cat1 + cat2*cat2) {
        printf("SIM");
    } else {
        printf("NAO");
    }
    return 0;
}

See running on ideone .