I know that using is used to release (give dispose ) resources. My question is in the following case:
public void FuncNaoFazNada()
{
using(var acd = new AlgumaClasseIDisposable())
{
return;
}
}
In this case, will the resources used by ACD be waived? Or will the flow break keep the resources allocated?
Yes, it is a syntax-sugar that works exactly like try-finally:
var acd = new AlgumaClasseIDisposable();
try
{
return FazAlgumaCoisa(acd);
}
finally
{
acd.Dispose();
}
The answer is: it will be released yes.
using in C # is a syntactic sugar, which is nothing more than a try ... finally at the end, where this code is:
public void FuncNaoFazNada()
{
using(var acd = new AlgumaClasseIDisposable())
{
return;
}
}
It will indeed be:
public void FuncNaoFazNada()
{
var acd = new AlgumaClasseIDisposable();
try{
return;
}
finally{
acd.Dispose();
}
}
So despite return within try , it will always execute the finally code block.
Tip: To better understand how the code implements the second form of code and debug line by line. This way you will understand how the execution flow is.