How to list files in PHP with a specific name?

Question

How to list files in PHP with a specific name?

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#1 by (6 votes)

2

Good Morning I have the code below.

 <?php
 $diretorio = "../../arquivos/nest"; 
 $ponteiro  = opendir($diretorio);
 while ($nome_itens = readdir($ponteiro)) {
$itens[] = $nome_itens;
}
sort($itens);
foreach ($itens as $listar) {
if ($listar!="." && $listar!=".."){ 
            if (is_dir($listar)) { 
                    $pastas[]=$listar; 
            } else{ 
                    $arquivos[]=$listar;
            }
   }
}
if ($pastas != "" ) { 
foreach($pastas as $listar){
print "<img src='pasta.png'> <a href='$diretorio/$listar'download>$listar</a><br>";} 
   }
if ($arquivos != "") {
foreach($arquivos as $listar){
print "<a href='$diretorio/$listar' download>$listar</a><br>";}
}
?>

The Code works correctly, my doubt is. I want to create a variable that will have a specific text and that will serve as a filter to show the files it has in the directory with the variable in question.

Example: In the variable contain the information "Cars", when generating the listing only the files in the directories that have in the name of the "Cars" files appear.

php

asked by anonymous 09.03.2017 / 12:54

1 answer

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score 6 · Accepted Answer

I think you've done it in a more complicated way.

It was simpler to use the glob function containing the desired expression:

 $expr = '/caminho/para/pasta/Carros*.txt';

 foreach (glob($expr) as $path) {
       echo $path;
 }

Another way is to use the strpos function to see if you have the desired part in the file name.

In the case, I'll use a more current way to list directories, which is through FileSystemIterator

$arquivos = array();
$termo = 'Carros';
$iterator = new FileSystemIterator('diretório/desejado/aqui');
foreach ($iterator as $file) {

      $filename = $file->getRealpath();

      if (strpos($filename, $termo) !== false) {
         $arquivos[] = $filename;
      }
}