package aulas;
public class Aula{
public static void main(String[] args){
for(int i = 0, j = 0; i < 100 || j < 50; ++i);
//Quando troco o operador lógico para && é impresso até 99, porém
//quando uso || é impresso até o infinito(ou estouro da variável)
}
}
Why is the condition of j never satisfied with "||", and why is i satisfied with "&&"?
2
asked by anonymous 20.08.2017 / 03:54
2 answers
6
The question is as follows, you are incrementing only the value of the i variable. This way it will vary from 0 to 99 .
These are the true tables for the logical connectives:
E (& &)
A | B | A && B
--+---+-------
V | V | V
V | F | F
F | V | F
F | F | F
OU (||)
A | B | A || B
--+---+-------
V | V | V
V | F | V
F | V | V
F | F | F
Thus, as can be seen in the OU (||) operator, both conditions must be false for the loop to stop. Because the value of the j variable is never incremented. The loop is infinite causing the overflow.
In the E (&&) operator, only one of the evaluations must be false to make the Boolean expression false, and thus break the loop, a fact that will occur only when the value of i is 100.
20.08.2017 / 04:04
1
Because the value of j is static.
You only have i++ so j will always meet the proposed condition
20.08.2017 / 04:02