How do I stop organizing this table? Sum, subtraction and multiplication respectively?
#include <stdio.h>
int main (){
int i=0, num=0;
printf ("Digite um n£mero: ");
scanf ("%d",&num);
printf ("\n");
while (i<=9){
i++;
printf ("%d + %d = %d\n", i, num, num+i);
printf ("%d - %d = %d\n", i, num, i-num);
printf ("%d X %d = %d\n", i, num, num*i);
}
}
Just replace '\ n's' from the first and second printf with' \ t's, this way it will not do the line break, which in the case is' \ n ', and still give a tab, in case o \ t , (equivalent to four spaces).
#include <stdio.h>
int main ()
{
int i=0, num=0;
printf ("Digite um n£mero: ");
scanf ("%d",&num);
printf ("\n");
while ( i <= 9 )
{
i++;
printf ("%d + %d = %d\t", i, num, num+i);
printf ("%d - %d = %d\t", i, num, i-num);
printf ("%d X %d = %d\n", i, num, num*i);
}
return 0;
}
In this case the output will look like this:
otherway:
#include<stdio.h>#include<locale.h>intmain(){inti=0,num=0;setlocale(LC_ALL,"");
printf ("Digite um número: ");
scanf (" %d", &num);
printf ("\nAdição:\n");
for ( i = 0; i <= 9; i++ )
printf ("%d + %d = %d\n", i, num, num+i);
printf ("\nSubtração:\n");
for ( i = 0; i <= 9; i++ )
printf ("%d - %d = %d\n", i, num, i-num);
printf ("\nMultiplicação\n");
for ( i = 0; i <= 9; i++ )
printf ("%d X %d = %d\n", i, num, num*i);
return 0;
}
In this way the output will be sequential, I added the locale.h library to use accent, the command setlocale(LC_ALL, ""); is the command that allows the BR accents to be used, the image of this output is this:
