I would like to know how I can transform an Object Array into a Simple Array only with a certain value.
I have this:
const names = [
{id:0, name:"Jean"},
{id:2, name:"Ricardo"},
{id:4, name:"Letiiicia"},
{id:5, name:"Dai"},
{id:7, name:"Tamy"},
{id:10, name:"Abeu"},
I wanted to return this to:
const names /*ou um novo array, não sei*/ = ['Jean','Ricardo','Leticia','Dai','Tamy','Abeu']
A new array only with names . Could someone help me?
The simplest is to use the % w / Array , which was precisely for this type of situations that was created. This allows you to get a new array based on a transformation of the current array.
In your case it would be something like:
names = persons.map(function(person){
return person.name;
});
Where map would be the array of objects it had initially. The persons will call the function passed to each element of the array, and construct a new one with the returns obtained for each element.
With Arrow Functions gets even more straightforward, simple and easy to read:
names = persons.map(person => person.name);
We can read as follows: map is mapped with each persons being person .
See it working:
const persons = [
{id:0, name:"Jean"},
{id:2, name:"Ricardo"},
{id:4, name:"Letiiicia"},
{id:5, name:"Dai"},
{id:7, name:"Tamy"},
{id:10, name:"Abeu"}
];
const names = persons.map(person => person.name);
console.log(names);One way to do this is as follows:
var novoArray = []
for (i = 0; i < names.length; i++) {
novoArray.push(names[i].name);
}
You can do this:
function myFunction(){
const obj = [
{id:0, name:"Jean"},
{id:2, name:"Ricardo"},
{id:4, name:"Letiiicia"},
{id:5, name:"Dai"},
{id:7, name:"Tamy"},
{id:10, name:"Abeu"}]
const names = obj.map(function(item) {
return item['name'];
});
alert(names);
}