I have the following string:
JOSÉ CARLOS ALMEIDA (0-2) 1
I need to remove the text and spaces and leave (0-2) 1
This way I can deal with trim , split etc ...
But my string will not always be the same as the times can come:
JOSÉ SAMUEL (0-2) 1
and or
CARLOS MANGUEIRA (0-2) 1
How can I handle these variations?
Assemble a substring with the opening index in the opening parentheses and that goes all the way.
str = 'CARLOS MANGUEIRA (0-2) 1' # string de exemplo
index = str.find('(') # indice comecando na abertura de parenteses
substr = str[index:] # substring que vai do indice até o fim da string de exemplo
print substr
Result:
(0-2) 1
It works regardless of the number of digits inside the parentheses.
You can also do with regular expressions, assuming the pattern is always the same:
(número-número) número
Where número would be any sequence of digits (i.e. nonnegative integers), regex would look like:
\(\d+\-\d+\)\s\d+
Extracting the contents of the strings:
import re
values = [
"JOSÉ CARLOS ALMEIDA (0-2) 1",
"JOSÉ SAMUEL (3-4) 7",
"CARLOS MANGUEIRA (2-10) 99"
]
for value in values:
result = re.search(r"\(\d+\-\d+\)\s\d+", value)
if result:
print(result.group(0))
The output is:
(0-2) 1
(3-4) 7
(2-10) 99
See working at Repl.it .