Grep with multiple parameters

You can use the [] delimiters, which get all the characters inside them (the \ must be escaped, so it gets \ ):

grep -e "[\|]" 

See examples of this regex here .

As reported in the comments, grep also works without the -e option and does not need to escape the bar:

grep "[\|]" 

You can use the regular expression [\|] , see:

grep:

$ diff -y ontem.csv hoje.csv | grep '[\|]'

egrep:

$ diff -y ontem.csv hoje.csv | egrep '[\|]'

awk:

$ diff -y ontem.csv hoje.csv | awk '/[\|]/{print}'

perl:

$ diff -y ontem.csv hoje.csv | perl -nle 'print if m{[\|]}'

sed:

$ diff -y novas.csv entrada.txt | sed -n '/[\|]/p'

Follows:

diff -y ontem.csv hoje.csv | grep "[|\]"

See more at & > link

You can also use egrep - > link