Problems with sort () and knockoutjs

Well, the parameter a and b of sort is an object, as such you should invoke the function as the number is an observable:)

Here's a working example, I hope you realize what the error was!

link

Hello, funcaoDeComparacao(objA, objB) of .sort(funcaoDeComparacao) waits as an integer to return the array order.

If we compare two objects, the comparison rule returns a small number (relative to other comparisons), it will be moved to the beginning of the array.

If the return is a larger number (than the other comparisons), it will be moved to the end of the Array.

So to make it easier to compare objects, we usually return -1 when objA should appear before objB , 0 when objA is equal to objB or 1 when objA should appear after objB .

Note that self.numeros is not an array of integers, but an array of objects of type ranum , which has a property called numero , worth noting that numero is not a integer, but a function that returns one.

Then to perform the ordering of the expected form, do the following:

self.organizar = function() {
  self.numeros.sort(function(a, b) {
    var numeroA = a.numero();
    var numeroB = b.numero();
    return numeroA - numeroB;
  });
}