list assignment index out of range

Question

list assignment index out of range

Navigation

#1 by (2 votes)

3

A part of my Python program is:

dt=1
maxt=3600*2
t=range(0,maxt,dt)
r=len(t)
Tsup_i=20

for i in range(1,r):
    Tsup[0]=Tsup_i
    P[i]=((I_dc)**2) * R20 * (1 + a * (Tsup[i] - (20+K)))

And the error is appearing

"IndexError: list assignment index out of range"

In the line corresponding to Tsup[0]=Tsup_i and I do not know how to solve ...

The Tsup I put before the cycle for as an empty list Tsup=[] , and what I want is that the 1st element of the list is equal to Tsup_i , that gives to determine P[i] e later in the code you can determine Tsup[i+1] using P[i] .

python lista python-2.7

asked by anonymous 15.02.2016 / 11:51

1 answer

What sublime plugin name 2/3 that indicates syntax error in the php language? How to identify exactly which record has changed from one list to another? By ID

score 2 · Accepted Answer

Tsup is an empty list and you try to access your first element by Tsup[0] . To associate a new element with it the correct one is use the function append() :

Tsup.append(Tsup_i)

But be aware that within for it will add a new element to each iteration, creating Tsup[0] , Tsup[1] , .... to Tsup[r] . If you want to associate only the first element you can do it outside of your for cycle.