I need to do this sequence in a repeat structure to use with a bigger N, but I can not do it, does anyone have any idea how to do this?
n=8
names <- c (seq(1 , n), seq(2,n+1 ), seq (3,n+2), seq(4 ,n+3), seq(5,n+5 ),seq(6,n+5),seq(7, n+6 ), seq (8,n+7))
Thank you in advance ..
If what you want is a way to make the sequence more dynamic, you can use the following:
n=8
names <- rep(1:n, n)+rep(0:(n-1), each=n)
#[1] 1 2 3 4 5 6 7 8 2 3 4 5 6 7 8 9 3 4 5 6 7 8
#[23] 9 10 4 5 6 7 8 9 10 11 5 6 7 8 9 10 11 12 6 7 8 9
#[45] 10 11 12 13 7 8 9 10 11 12 13 14 8 9 10 11 12 13 14 15
In this way you create the sequence 1:n n times, and add 0, 1, 2...n-1 to each 1:n .
Complementing with yet another answer option, you can also use lapply .
criar_seq <- function(x){
seq(x, (n+x-1))
}
n <- 8
lapply(1:n, criar_seq)
This will return a list of n sequences with the progression of one more. If you want to put the data as a vector, just apply unlist .