Compact and uncompress file in memory

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I have several functions that read the file directly from a cache path , but eventually it will cost a lot of space on filesystem , is there any way to generate this file in memory and save it already zipped to disk? >     

asked by anonymous 10.01.2017 / 16:37

1 answer

4

Well if I understood correctly you can do the following: 

from zipfile import *
import os

zip_name = 'my_zip.zip' # caminho para o zip
file_to_zip = 'file.txt' # caminho para o ficheiro a inserir no zip

if(not os.path.isfile(file_to_zip)):
    print('ficheiro {} nao existe, operacao cancelada'.format(file_to_zip))
else:
    with ZipFile(zip_name, 'w') as myzip: # criar um zip
        try:
            myzip.write(file_to_zip) # inserir ficheiro no zip
            os.remove(file_to_zip) # apagar ficheiro
        except Exception as err:
            print(err)
        else:
            print('Execucao bem sucedida, {} zipado em {}'.format(file_to_zip, zip_name))

I do some checks that I consider important, if(not os.path.isfile(file_to_zip)) will be to ensure that there is a new zip file, because if it does not exist we do not want to delete the previous zip ( with ZipFile(zip_name, 'w') ), os.remove(file_to_zip) here delete the file ancient

    
10.01.2017 / 17:33
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