In PHP, how can I reference the first for from the second, as in the example below?
for ($i=0; $i < 10; $i++) {
for ($j=0; $j < 10; $j++) {
// Quero que esse afete o primeiro 'for' e não o segundo
if ($j == $i) continue;
echo $j;
}
}
I learned how to do this using the Kotlin , but is there any way to do something similar in PHP?
You can use a number in continue to identify which loop you want to stop / continue.
This works for break and switch too. And it is counted from the inside out, for example: the innermost loop is the 1.
Example:
for ($i=0; $i < 3; $i++) {
echo 'externo' . PHP_EOL;
for ($j=0; $j < 3; $j++) {
// Quero que esse afete o primeiro 'for' e não o segundo
if ($j == $i) continue 2;
echo "$i - $j" . PHP_EOL;
}
}
Yes, you can use continue 2; , you can see this in documentation on control structures .
The continue accepts an optional numeric argument that tells you how many levels of nested loops to skip. The default value is 1, jumping to the end of the current loop.
This feature also works for break and switch , and counts from the inside out, ie: the inner loop is 1 .
for ($i=0; $i < 10; $i++) {
for ($j=0; $j < 10; $j++) {
if ($j == $i) continue 2;
echo $j;
}
}
// dá: 001012012301234012345012345601234567012345678
Ideone: link
Try to use like this, It should work
if ($j == $i) continue 2;
In the PHP manual:
Continue accepts an optional numeric argument that tells how many levels of nested loops should skip. The default value is 1, jumping to the end of the current loop ... Documentation
The same thing applies to the break .
break accepts an optional numeric argument that tells how many structures should stop. The default value is 1, only the structure immediate interruption.