How to get the values of a <textarea> with Regex, including new line?
I have the following expression to get a textarea :
([<]textarea.*[<\/textarea][>])
The problem is that if textarea has a line break, the expression can not catch it.
From here my question: How to capture textarea with new line?
The problem with this REGEX is that by default . does not include \n , this way it would have to get around this fault, it could be with deny [^...] , which captures anything that is not in the group. p>
For your needs you can do this: <(textarea)([^>]*)>([^%]*?)</> .
See working at REGEX101
<(textarea) - literally captures < and generates a literal group with textarea , which will be used as a shortcut. ([^>]*)> - will be all attributes of the tag, remembering that attributes do not have > so I used his negation to get everything, finally it should end with the term of tag > . ([^%]*?) - here is content to be captured, I have used the % deny since I do not want to have this in the middle, but if you have just change to another character, for example ¬ , remembering that because it is Deny includes any and all characters that are not in the group including \n . </> - finally must catch the end of the tag. which was resumed with the shortcut of the group 1 You can also use the s flag to allow . (Dot) to capture \n .
changing REGEX to <(textarea)([^>]*)>(.*?)</> .
Remembering that% s of% should apply.
string.match(/<(textarea)([^>]*)>(.*?)<\/>/gs); // aqui foi necessário escapar o '/', para não ser interpretado como fim da REGEX '<\/>'.
See working at REGEX101
You can do this:
(<textarea[\s\S]+?textarea>)
The important part is [\s\S]+? , which basically allows everything , one or more times, and ? says to be lazy and achieve capture in the first opportunity you encounter. >
The other answers are correct and excellent, I just made some changes:
I've modified the @Sergio example to:
/(<textarea[\s\S]+?<\/textarea>)/g
Test: link
This to avoid things like <textarea>abc<textarea> (see that the bar is missing, but in the original @Sergio regex I was getting the match)
If you need to match attributes and content separately, do so:
/(<textarea([^>]+)>([\s\S]+?|)<\/textarea>)/g
I've modified the @GuilhermeLautert example to:
/<(textarea)([^>]+)>([^%]*?)<\/>/g
Test: link
The answer works perfectly, but if you need to use / it will not work well due to </> , of course the situation varies in different languages, this is just for a specific situation.
Note: I came up with an example, but my knowledge was more limited, however follow the regex:
<textarea([^>]+)[>]([^<]+[^t]+[^e]+[^x]+[^t]+[^a]+[^r]+[^e]+[^a]+[^>]|.*)<\/textarea>Result: link
However the other answers show better and simpler ways, this is just an alternative to study
Hello friend, I was able to do this:
<textarea\b[^>]*>((\n*|.)*)<\/textarea>
Example: link
<textarea\b[^>]*> Capture the first tag, the \b border ensures that the tag matches <textarea . [^>]* matches all characters except > preventing the tag from containing two >>
((\n*|.)*)) Captures the Group of the tag content. Capture any line break \n* or | catch all characters .*
<\/textarea> Ends with capture of closing tag