How to check if a value is present inside an array?

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3
$idofdb = "25";

$myArray = array();
foreach ( $fthi as $codigo ) {
    $myArray[] = $codigo['ImoCodigo'];
}

$checkValues = array_values($myArray);
$checkString = implode(',', $checkValues); // 3,4,5,6,7,8,9,10,11,12,13,18,19,14,15,2

I'd like to know how to compare $idofdb with $checkString to see if $idofdb is registered in the database. As you can see, the output of $checkString is a string of numbers separated by commas.

    
asked by anonymous 29.11.2015 / 21:41

3 answers

3

You do not need all this, just use the in_array() function directly in array : 

in_array("25", $fthi)

Or if you feel you should do something else for some reason: 

in_array("25", $checkValues)

See running on ideone .

    
29.11.2015 / 21:53
2

Instead of you transforming an array into a string with comma-separated numbers you can use the in_array : 

<?php

$os = array("Mac", "NT", "Irix", "Linux"); 
if (in_array("Irix", $os)) { 
    echo "Tem Irix";
}
if (in_array("mac", $os)) { 
    echo "Tem mac";
}

?>

Look at the PhpFiddle showing execution.

    
29.11.2015 / 21:53
1

As friends have said, this is not necessary. But if you still want to check in string , you can use strpos 

$pos = strpos($checkString, $idofdb);

if($pos == false) {
    echo 'Não tem cadastrado';
}else{
    echo 'A string foi encontrada na db';
}
    
29.11.2015 / 21:55
Get multiple values from a multi select select pdo with oo