How to generate an array of years dynamically containing the index as the year and the value as the year itself?

Question

How to generate an array of years dynamically containing the index as the year and the value as the year itself?

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#1 by (4 votes)
#2 by (2 votes)

3

I have a routine that generates a list of years dynamically from an initial year defined in the array which in this case is the year 2015 up to the current year.

View array structure:

$rray = array(
            "1" => "2015" #Ano inicial
        );

Routine that generates list of years:

<?php
$rray = array(
            "1" => "2015"
        );

$ano = $rray[1];
$i = 1;

while ($ano <= date("Y")) {
    $rray[$i] = $ano;
    $ano++;
    $i++;
}

print_r($rray);

The above routine generates the following output array:

Array
(
    [1] => 2015
    [2] => 2016
    [3] => 2017
)

But I would like indexes that are numeric [1] [2] [3] to be the year itself.

Instead of being

Array
(
    [1] => 2015
    [2] => 2016
    [3] => 2017
)

I would like it to be

Array
(
    [2015] => 2015
    [2016] => 2016
    [2017] => 2017
)

In what way could I do this?

php array

asked by anonymous 02.02.2017 / 19:58

2 answers

2

You can do that too, very simple.

Code:

<?php

$rray = array();
$ano = '2015';

while ($ano <= date('Y')) {
    $rray[$ano] = $ano;
    $ano++;
}

print_r($rray);

?>

Output:

Array
(
    [2015] => 2015
    [2016] => 2016
    [2017] => 2017
)

02.02.2017 / 20:11

Factor function in C does not return result Typedef struct with C character vector is not working

score 4 · Accepted Answer

You can use range() to generate the list of years and array_combine() to transform the value of $keys into the keys themselves:

$keys = range(2015, 2020);
$arr = array_combine($keys , $keys);

Or:

$year = date('Y');
$keys = range($year, $year + 10);
$arr = array_combine($keys , $keys);

Output:

Array
(
    [2015] => 2015
    [2016] => 2016
    [2017] => 2017
    [2018] => 2018
    [2019] => 2019
    [2020] => 2020
)