Show hexadecimal value in cmd.exe

The printf is showing hexadecimal because you used "% x", which is just that! Show value in hexadecimal:)

Just use this way, in the case of your example:

printf("%c" ,eh);

Remembering that in C ++ 11 you can use UTF-8 directly in code:

char* acentuada = u8"Acentuação";
printf("%s", acentuada);

It is important in this second to ensure that your code editor is configured for UTF-8.

  

Remember that in both cases, the way your environment is set up (code page, encoding pattern) can affect the output even if the input and code are right.

Of curiosity here are the main formats of printf:

d ou i  Inteiro decimal com sinal                         392
u       Inteiro decimal sem sinal                        7235
o       Octal sem sinal                                   610
x       Inteiro hexadecimal sem sinal                     7fa
f       Ponto flutuante decimal                        392.65
e       Notação científica                          3.9265e+2
g       %e ou %f automático (o que for mais curto)     392.65
c       Caractere                                           b
s       Cadeia (string) de caracteres                   teste
p       Endereço de ponteiro                         ba000000

Correct is to use %c to display the character, %s is used to display a string of strings .

unsigned char eh = 0x82;
printf("%c", eh);