I have the following code:
$msg = "teste";
$myfile = fopen("lista.txt", "w");
fwrite($myfile, $msg."\n");
fclose($myfile);
If I change the value of the variable $msg it opens the file deletes the $msg previous and replaces it with the new value. How can I keep both?
Example of how I want the output inside the file txt :
teste
novo valor
You should open the file to add and not to write:
$msg = "teste";
$myfile = fopen("lista.txt", "a");
fwrite($myfile, $msg."\n");
fclose($myfile);
At least this is the simplest form if you just want it. If you want to do multiple operations then you need a slightly more sophisticated algorithm to manage the positioning in the file.
Another possibility is to use file_put_contents() with argument FILE_APPEND , thus avoiding file control.
Documentation:
The file_put_contents function can be used to do this in a simpler way. According to the PHP documentation, this function is the same as calling the fopen, fwrite, and fclose functions:
This function is identical to calling fopen (), fwrite () and fclose () successively to write data to a file.
That is, this function serves as a simplified way of writing data to a file.
$msg = 'teste' . PHP_EOL;
file_put_contents('lista.txt', $msg, FILE_APPEND);
The constant FILE_APPEND is used to add new content without deleting the existing one. Therefore, if the function is executed again with a different value, the "teste" value will not be erased.
PS: Remembering that the constant PHP_EOL is used to add a line break (independent of the operating system).