How do I get the name of the variable used in the function argument?

With the PHP 5.6 update, the " Variadic functions via was released. .. "
I was able to create a clean and clear code:

• Script1.php

  $variavel = 'foo';
  sendData($variavel);
  

• Script2.php

  public function sendData(...$variables){
      foreach($variables as $variableValue){
          foreach($GLOBALS as $globalName => $globalValue){
              if($globalValue === $variableValue){
                  global $$globalName;
              }
           }
      }
  
      include('script3.php');
  }
  

• Script3.php

  echo($variavel);
  

For this code to work, the function must be called with the variable in a global scope. For example: if the function is called inside another function this code does not work, unless you declare the variable sent as global. eCode:

sampleMethod(){
    $variavel = 'bar';
    global $variavel;
    sendData($variavel);
}

There is another method to get the name of the variable with debug_backtrace () , but I think the question has already been answered.

In script3 declare the variable with the same global name, whether or not that class will make access in script3 will work!

I think it is not possible, the only alternative that occurs to me, would be to pass the name of the variable as a string in the parameter:

$variavel = 'Olá mundo!';

sendData('variavel');

function sendData(){
    $getFirstArgumentValue = func_get_arg(0);
    global $$getFirstArgumentValue;
    include('script3.php');
}

script3.php

<?php

echo($variavel);

?>

But anyway you will be limited to the variable always have this name: $variavel and I think your problem is that you need to apply the sendData() function to other variables, so you should use something like this:

$outra_variavel = 'Olá mundo!';

sendData($outra_variavel);

function sendData($data){
    include('script3.php');
}

script3.php

<?php

echo($data);

?>

Note that in this example it is not necessary to set the $data variable to global, because doing include('script3.php'); within the sendData function will be in the same scope, ie it is the same as

$outra_variavel = 'Olá mundo!';

sendData($outra_variavel);

function sendData($data){
    echo($data);
}

What you probably want to do is to have a script3.php template and load the required information through the sendData function, if this is the case you can do as follows.

function sendData(array $data = array()) {
    extract($data);
    include 'script3.php';
}

You'll have to set a% of style%:

$myData = array(
    'var1' => 'valor',
    'var2' => 'xpto',
);

So you can call the function array

So you can use the variables you need in script3.php , eg:

echo $var1;

if (isset($var2)) {
    echo 'var2 também existe com o seguinte valor: ' . $var2;
}

PS: If you want the sendData($myData); function to return the result generated by sendData as a string, you can do the following:

/**
 * Sends some data
 * @param  array  $data Variáveis a utilizar
 * @return string       Resultado
 */
function sendData(array $data = array()) {
    ob_start();
    extract($data);
    include 'script3.php';
    return ob_get_clean();
}

Try this:

script1.php

$data['variavel'] = 1;
getData($data);

or

getData(array('variavel'=>1));

script2.php

function getData($arr){
     extract($arr);
     include 'script3.php';
}

script3.php

echo $variavel;

Any index you set in the array that goes as a parameter to the getData() function will be created by the extract() command in the script3.php file

Documentation: link