Moon print (table) in string (taking all its values)

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Moon print (table) in string (taking all its values)

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#1 by (2 votes)

4

I created a system quickly to test a new variable, but I do not know how to print the users inserted in the table, and when I give print it shows this: table: 0035AE18

My code:

Conta = {balance = 0}
Contas = {}
Senhas = {}
Inicial = 5000
function Conta:withdraw (v)
Conta.Balance = Conta.Balance - v
end

function Login()
io.write("Digite seu Usuario\n")
usuariol = io.read()
io.write("Digite sua senha\n")
senhal = io.read()

for i=0, #Contas do
for j=0, #Senhas do
if usuariol == Contas[i] and senhal == Senhas[j] then
io.write("Logado com sucesso!")
Cadastro()
end
end
end
end

function Cadastro()
io.write("Ola, seja bem vindo ao sistema de Banco 1.0 By Charles \n")
io.write("Deseja criar uma conta? \n")
resposta = io.read()

if resposta == "sim" or resposta == "Sim" then
io.write("Ok, informe seu nome de usuario \n")
usuario = io.read()
io.write("Informe sua senha \n")
senha = io.read()
io.write("Aguarde um instante!\n")
if #Contas == 0 and #Senhas == 0 then
table.insert(Contas, 1, usuario)
table.insert(Senhas, 1, senha)
else
table.insert(Contas, usuario)
table.insert(Senhas, senha)
end
Login()

elseif resposta == "tabela" then
print(#Contas)
print(#Senhas)
end
end

Cadastro()

The system works like this: it creates the account, then you log in to it for account creation.

Let's suppose I created 3 accounts and then in the "you want to create account" part I type "table" it will show me the number of accounts and passwords created.

But I want to display them not in capacity size but by string . Ex:

t = {'teste'}
print(t)

Console:

table: test

lua lua-table

asked by anonymous 26.01.2015 / 22:13

1 answer

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score 2 · Answer 1

I think this is what you want:

Conta = {balance = 0}
Contas = {}
Senhas = {}
Inicial = 5000
function Conta:withdraw (v)
    Conta.Balance = Conta.Balance - v
end

function Login()
    io.write("Digite seu Usuario\n")
    usuariol = io.read()
    io.write("Digite sua senha\n")
    senhal = io.read()

    for i=0, #Contas do
        for j=0, #Senhas do
            if usuariol == Contas[i] and senhal == Senhas[j] then
                io.write("Logado com sucesso!")
                Cadastro()
            end
        end
    end
end

function Cadastro()
    io.write("Ola, seja bem vindo ao sistema de Banco 1.0 By Charles \n")
    io.write("Deseja criar uma conta? \n")
    resposta = io.read()

    if resposta == "sim" or resposta == "Sim" then
        io.write("Ok, informe seu nome de usuario \n")
        usuario = io.read()
        io.write("Informe sua senha \n")
        senha = io.read()
        io.write("Aguarde um instante!\n")
        if #Contas == 0 and #Senhas == 0 then
            table.insert(Contas, 1, usuario)
            table.insert(Senhas, 1, senha)
        else
            table.insert(Contas, usuario)
            table.insert(Senhas, senha)
        end
        Login()

    elseif resposta == "tabela" then
        for i,v in ipairs(Contas) do
            print(v)
        end
        for i,v in ipairs(Senhas) do
            print(v)
        end
    end
end

Cadastro()

See running on ideone .

I used the most recommended technique to scan all array but you could use the same one you used to check if user and password are registered.

I think you should review how this data is stored.

Your code will bring memory problems (roughly speaking) in the way it is organized.

There are a few other issues but I think you're still going to mess with it a lot.