Images are repeating in ImageViews

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Images are repeating in ImageViews

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#1 by (2 votes)

4

I have 54 images I need to show only 8, but there has to be a random selection and they can not be repeated, I'm programming on the Android Studio platform.

I use this code it works quietly, it shows the results in 8 ImagemView , More .... it repeats the results of the image;

insira o código aqui


public void Button2(View view) {

        final int[] imageViews = {
                R.id.imageView, R.id.imageView4, R.id.imageView7,
                R.id.imageView2, R.id.imageView5, R.id.imageView8,
                R.id.imageView3, R.id.imageView6,};


        final int[] images = {

                R.drawable.1,
                R.drawable.2,
                R.drawable.3,
                R.drawable.4,
                ...... vai até o 54


        };


        final Button shuffle = (Button) findViewById(R.id.Button2);
        shuffle.setOnClickListener(new View.OnClickListener() {
            public void onClick(View view) {
                Random generator = new Random();
                int n = 9;
                n = generator.nextInt(n);
                Random random = new Random(System.currentTimeMillis());
                for (int v : imageViews) {
                    ImageView iv = (ImageView) findViewById(v);
                    iv.setImageResource(images[generator.nextInt(images.length - 1)]);
                }
            }
        });
    }

insira o código aqui

I used this Code below to solve the problem.

};

final Button shuffle = (Button) findViewById(R.id.Button4);
shuffle.setOnClickListener(new View.OnClickListener() {
    public void onClick(View view) {

        Random rng = new Random();
        List<Integer> generated = new ArrayList<Integer>();
        for (int i = 0; i < 8; i++)
        {
            while(true)
            {
                Integer next = rng.nextInt(54) ;
                if (!generated.contains(next))
                {
                    generated.add(next);
                    ImageView iv = (ImageView)findViewById(imageViews[i]);
                    iv.setImageResource(images[next]);
                    break;
                }
            }
        }
    }
});}}
insira o código aqui

Source: link

random java android

asked by anonymous 14.09.2016 / 04:28

1 answer

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score 2 · Accepted Answer

You can do this by comparing whether the generated number already exists in ArrayList :

int totalImagens = 54;
int totalEscolher = 10;
ArrayList<Integer> numbers = new ArrayList<Integer>();
Random randomGenerator = new Random();
while(numbers.size() < totalEscolher)
    {
        int random = randomGenerator.nextInt(totalImagens);
        if (!numbers.contains(random)) {
            numbers.add(random);
        }
}

Thinking in this way, your setOnClickListener would look like this:

final Button shuffle = (Button) findViewById(R.id.Button2);
        shuffle.setOnClickListener(new View.OnClickListener() {
            public void onClick(View view) {

                int totalImagens = images.length;
                int totalEscolher = 10;
                final ArrayList<Integer> numbers = new ArrayList<Integer>();
                Random randomGenerator = new Random();
                while(numbers.size() < totalEscolher)
                {
                    int random = randomGenerator.nextInt(totalImagens);
                    if (!numbers.contains(random)) {
                        numbers.add(random);
                    }
                }

                for (int v : numbers) {
                    imageViews[v] = images[numbers.get(v)];
                    ImageView iv = (ImageView) findViewById(v);
                    iv.setImageResource(imageViews[v]);
                }
            }
        });