How do I delete a particular character in a particular position in the shell?
I've tried with sed , but I can not put the position too, just the default.
",45123","B23142DHAS675"
What I wanted was to delete the , that is in the second position of the string, but if there is no , nothing should be done.
You can do this:
~$ echo ",45123","B23142DHAS675" | sed 's/.//7'
,45123B23142DHAS675
Where 7 is the position of the character to be removed. Another alternative:
~$ echo ",45123","B23142DHAS675" | sed 's/\,//2'
,45123B23142DHAS675
The above command removes the second occurrence of , .
Use a regular expression that stores the first% w / o% characters, make sure that the n - 1 character is what you want, and save the remaining characters.
echo "abcdef nao sera removido
a,cdef será removido
A,BCD será removido" | sed -r 's/^(.),(.*)$//'
Result:
abcdef nao sera removido
acdef será removido
ABCD será removido