I have the following list:
[['a:/, b:/, w:/, g:/, f:/, d:/Downloads/Torrent/End, x:/files.2t, y:/files.1t'], ['d:/Dropbox/project/rato_bat'], ['data']]
But I wanted it to be a list inside another list because I did this:
for a in lldir:
for b in a:
b = b.split(', ')
Would it be possible to do this in a row and assign it to a variable?
You want something like:
novo_conjunto = []
for a in lldir:
nova_lista = []
for b in a:
nova_lista.append(b.split(', '))
novo_conjunto.append(nova_lista)
a = novo_conjunto
If you want one line only:
a = [[elemento.split()] for elemento in lista] for lista in a]
If you want a single list with all the directory entries, all the sub-lists of the first entry:
diretorios = []
for lista in a:
for elemento in lista:
for diretorio in elemento.split(","):
diretorio.append(diretorio.strip())