I would like to know why you are not returning a table in the code I made:
TP = {}
function TP:new(pos, newpos, effect)
return setmetatable({pos = pos, newpos = newpos, effect = effect}, { __index = self })
end
function TP:setNewPos(position)
self.newpos = position
end
function TP:setEffect(efeito)
self.effect = efeito
end
var = TP:new({x = 160, y = 54, z = 7}, {x = 180, y = 60, z = 7}, 10)
print("is "..var.newpos) -- era para retornar uma tabela.
Values are not returned because you are attempting to concatenate a table object with a string using operator .. , to print the table values, do:
var = TP:new({x = 160, y = 54, z = 7}, {x = 180, y = 60, z = 7}, 10)
print ("is")
for chave, valor in pairs(var.newpos) do
print (chave, valor)
end
Alternatively you can create a function and return the table:
function TP:getNewPos()
return self.newpos
end
To use it, do so:
var = TP:new({x = 160, y = 54, z = 7}, {x = 180, y = 60, z = 7}, 10)
newpos = var:getNewPos()
print ("is")
for chave, valor in pairs(newpos) do
print (chave, valor)
end
The problem here is that you are trying to concatenate a string with a table, and that defines the metamethod to be called is the first operator. Fortunately for the case of strings, you can do an implementation in these metamethods that will work for what you intended there.
-- captura a metatable de string
local mt = getmetatable("")
-- faz override no metametodo __concat
mt.__concat = function(a, b)
if type(a) == "string" and type(b) == "table" then
local at = {}
for k, v in pairs(b) do
table.insert(at, k .. " = " .. v)
end
return a .. " {" .. table.concat(at, ", ") .. "}"
end
return a .. b
end
-- com o metametodo sobreposto
-- agora quando chamar o operador .. que é o operador de concatenação
-- a sua função costomizada será chamada no lugar da padrão
print("is:" .. {x=2, y = 2, z = 3})