Make a request on the server with 2 parameters

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-4

Well, I'm making a person use a "range" and decide a value, so the person changes the range, a search is being done in the database about a game and its value, use ajax with php to This, however, is giving you an error, can you help me?

    
asked by anonymous 26.11.2018 / 14:42

3 answers

1

Good morning,

So I just put the .value at the end of the document.getElementById ('game') 

var jogo = document.getElementById('jogo').value;

You are trying to send the game input and not the value of the field in that code

    
26.11.2018 / 16:20
0

Test there to verify that the request is going with both parameters.

"php / select-coach.php? value = 1 & game = 3" 

function criarReq() {
    try{
        return new XMLHttpRequest();
    } catch (e) {
        try {
            return new ActiveXObject("Msxml2.XMLHTTP");
        }catch (e) {
            try {
                return new ActiveXObject("Microsoft.XMLHTTP");
            }catch (e) {
                console.log("Seu navegador não suporta Ajax!");
                //return null;
            }
        }
    }
}

function getDados() {
    var valor = document.getElementById('coachValue').value;
    var coach = document.getElementById('coachs');
    var jogo = document.getElementById('jogo').value;
    var xmlreq = new criarReq();
    
    console.log("php/select-coach.php?valor="+valor+"&jogo="+jogo);
}
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
</head>
<body>
  <input type="range" id="coachValue" value="1">
  <input type="text" id="coachs" value="2">
  <input type="text" id="jogo" value="3">
  
  
  <input type="button" value="send" onclick="getDados()">
</body>
</html>
    
27.11.2018 / 01:46
-3

Friend, line 6 looks like this: 

$jogo=intval($_GET['jogo']);

change this part leaving it like this: 

$jogo=$_GET['jogo'];
    
30.11.2018 / 02:39
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