What's wrong? It was supposed to appear "worthless", but when it starts with zero it appears "too high" in the message.
<?php
$num = 0;
switch ($num){
case($num>100);
echo'valor muito alto';
break;
case($num<80 && $num>51);
echo'valor medio';
break;
case($num==50);
echo'valor perfeito';
break;
case($num<=10);
echo'valor muito baixo';
break;
case($num==0);
echo'sem valor';
break;
}
?>
case does not work the way you expect it to. It is not a replacement for if . See the documentation . The case only accepts a value, it only tests the equality of that value.
More or less what you want is this:
$num = 0;
if ($num > 100) echo 'valor muito alto';
else if ($num < 80 && $num > 51) echo 'valor medio';
else if ($num == 50) echo 'valor perfeito';
else if ($num <= 10) echo 'valor muito baixo';
else if ($num == 0) echo'sem valor';
See running on ideone . And no Coding Ground . Also I placed GitHub for future reference .
There is still a logic error there. You can not even understand what the goal is. It has overlapping ranges of values, ranges of values that are not reached by any of the conditions.
I tested it here and it worked, it is a gambiarra, but it meets your need, as I want to test more than one value in the case, I have to create an array like @Miero said, the case It does not work like that, but you can play a game.
Creating 3 arrays with the range of values you want, and testing whether the value exists inside the array using the in_array function, is nice ...
<?php
$num = 40;
$array100_80 = array();
$array79_51 = array();
$array49_1 = array();
for ($i = 80; $i <= 100; $i++) {
$array100_80[$i] = $i;
}
for ($i = 51; $i <= 79; $i++) {
$array79_51[$i] = $i;
}
for ($i = 1; $i <= 49; $i++) {
$array49_1[$i] = $i;
}
switch ($num){
case(0):
echo'sem valor';
break;
case(in_array($num, $array100_80)):
echo'valor muito alto';
break;
case(in_array($num, $array79_51)):
echo'valor medio';
break;
case(50):
echo'valor perfeito';
break;
case(in_array($num, $array49_1)):
echo'valor muito baixo';
break;
}