This is my programming line 17:
$result = mysql_query($localhost, "SELECT *FROM **nome do meu banco**")
or die (mysql_error());
This is the error I can not get:
Warning: mysql_query () expects parameter 2 to be resource, string given in / home / u803520287 / public_html / android / my name bank .php on line 17
How to fix?
It's basically a typo.
The PHP manual is clear in the order of the parameters:
mysql_query (string $query[, resource $link_identifier] )
More details:
It is suggested to change the functions mysql by mysqli , which are not obsolete (and in this case, the link comes first in these).
See more here: Improved MySQL Extension