Since the generation is random and independent of the previous ones, there is no way to predict the next sequence.
What we can determine is the probability that the next sequence is equal to one already output.
The number of possible combinations of 10 numbers taken from a set of 100 can be calculated by the following formula:
The result for this case is: 17310309456440
.
The probability of exiting a given sequence is: 1/17310309456440
.
The probability of leaving a sequence equal to one that has already exited is: n/17310309456440
.
Being n
the number of different sequences already exited.
After 3 days the probability of leaving an equal sequence is 3/17310309456440
which is still greatly reduced: 1/5770103152146
.
As the number of output sequences increases, the probability of a repeated output increases, but this fact (there are output sequences) does not influence the next output.
The probability of exiting a given sequence remains% w_ of%.