Why do not you want to increase?

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Why do not you want to increase?

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#1 by (4 votes)

-3

I want to increment the cont variable if the character vector is not null, understand? But nothing happens. Because?

#include <stdio.h>
#include <stdlib.h>
#include <string.h>


void main(){

int i;
char testeNome[190];
int cont;
printf("Digite seu primeiro nome: ");
scanf("%s",testeNome);


while(testeNome != "#include <stdio.h>
#include <stdlib.h>
#include <string.h>


void main(){

int i;
char testeNome[190];
int cont;
printf("Digite seu primeiro nome: ");
scanf("%s",testeNome);


while(testeNome != "%pre%"){

    cont++; 
    }

printf("%d",cont);
}
"){

    cont++; 
    }

printf("%d",cont);
}

c

asked by anonymous 21.04.2016 / 01:35

1 answer

Select separated by semicolons for xls How to translate a program in C to Assembly? [closed]

score 4 · Accepted Answer

Friend, follow the code working:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void main(){

int i = 0;
char testeNome[190];
int cont = 0;
printf("Digite seu primeiro nome: ");
scanf("%s",testeNome);

while(testeNome[i] != '#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void main(){

int i = 0;
char testeNome[190];
int cont = 0;
printf("Digite seu primeiro nome: ");
scanf("%s",testeNome);

while(testeNome[i] != '%pre%'){
    cont++;
    i++;
}

printf("%d",cont);
}
'){
    cont++;
    i++;
}

printf("%d",cont);
}

You forgot to use the variable i to treat the characters of the string, using it in testName and incrementing the i within the loop. Also, since \ 0 is a character, we need to indicate it in single quotation marks.

Aah, and it's always good to start variables (cont and i) with 0 to avoid having any value from a previous run.

I hope I have helped