I took a C book to study, however, it is a bit outdated, and I came across the following code:
#include<stdio.h>
is_in(char *s, char c);
void main(void){
is_in("olac", "ola");
}
is_in(char *s, char c){
while(*s)
if(*s == c) return 1;
else s++;
return 0;
}
link
Can someone help me?
On compilation error, there are missing the types in the prototype and function declaration:
int is_in(char *s, char c);
In the method call, you are passing a character string instead of a char.
is_in("olac", "ola");
The GCC compiles the code, but can not transform the inserted string. The correct would be:
is_in("olac", 'o');
Remembering that char always stays within plics (').
And about what the code does: it checks to see if a given character is present within a string. If positive, returns 1 (true); 0 negative (false) case.