Convert string "11092018" into date format "11-09-2018"?

Using the date_parse_from_format

$data = date_parse_from_format('dmY', '11092018');

$data['month'] = str_pad($data['month'], 2, 0, STR_PAD_LEFT);
$data['day'] = str_pad($data['day'], 2, 0, STR_PAD_LEFT);

$formatada = "{$data['day']}-{$data['month']}-{$data['year']}";

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Manual:

  

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Using class DateTime::createFromFormat

$data = DateTime::createFromFormat('dmY', '11092018');

$formatada = $data->format('d-m-Y');

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Manual:

  

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Using the preg_match

if (preg_match('/(\d{2})(\d{2})(\d{4})/', '11092018', $matches)) {
    echo "{$matches[1]}-{$matches[2]}-{$matches[3]}";
}

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Manual:

  

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There are many ways.

Using the substr

$formatada = substr($string,0,2).'-'.substr($string,2,2).'-'.substr($string,4,4);

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Manual:

  

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Using the substr_replace

$formatada = substr_replace(substr_replace($string,'-',4,0),'-',2,0);

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Manual:

  

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