I would like to know how I could check if the id of an inherited class equals an x value.
Something like:
class X {
id = 3;
}; ...
class Y {
id = 4;
};
I have a variant of any x, how could I check if x is equal to the id value of some class and call that instance.
The following code will illustrate how this works, from what I understand, this is what you need to understand the process ...
#include <iostream>
class foo{
protected:
int id;
public:
foo() : id(9) {}
virtual void printId(){ printf("%d\n",id); }
};
class oof : public foo{
public:
oof(){
id = 8;
}
};
class ofo : public foo{
public:
ofo() : foo(){}
void printId(){std::cout<<id<<"\tOFO"<<std::endl;}
};
class mofu : public ofo{
public:
mofu(){
id = 420;
}
};
int main(){
foo * a = new foo();
foo * b = new oof();
foo * c = new ofo();
foo * d = new mofu();
b->printId();
a->printId();
c->printId();
d->printId();
return 0;
}
Once you read it and run it, you'll better understand how the process works.
In order to do what you want, you would need some array {array, vector, list, stack ...} with all the instances that inherit this class and then have these instances just iterate over the structure until you find the what do you want. something like this:
class foo{
protected:
int id;
public:
foo() : id(9) {}
virtual void printId(){ printf("%d\n",id); }
virtual int getId(){ return id; }
};
...
//função que pega um foo * objects[], o tamanho desse array, e um numero para a seleção, e sempre que achar a instancia de 'foo' ele chama o printId();
void selectAndExec(foo ** objects, int arrayLength, int baseArg = 9){
for(int i = 0; i < arrayLenth; i++){
if(objects[i]->getId() == baseArg) objects[i]->printId();
}
}
The default argument is optional, it is only a basis for being able to call the function without passing an id, and it would be 9.
This is one of the ways to do this, if you think a little more about this problem is very easy to find better solutions because it depends a lot on what you want with the software.