I need to format a value for date ... I search for the following value link:
20181107
In case it would be 07/11/2018, today. I need to get this value and format it in 2018-11-07 format, I tried it as follows:
date('Y-m-d', strtotime('20181107'));
But in some cases it puts the day in the place of the month, then I wanted a solution for that or just a code that inserted a hyphen after 4 digits and after 6 digits, it would be simpler too.
You can use the createFromFormat function of the DateTime object:
<?php
echo DateTime::createFromFormat('Ymd', '20181107')->format('Y-m-d');
?>
In this way you can define the input format, and in the format function, you define the output format.
See working at Ideone .
You can also see more about createFromFormat here .
Nicholas,
You can use a common substring to do this, if your case is just string formatting, follow below:
substr("20181107",0,4)."-".substr("20181107",4,2)."-".substr("20181107",6,2)
It has already been replied, but if you prefer the procedural way, you can do this:
$date = date_create_from_format('Ymd', '20180120');
echo date_format($date, 'Y-m-d');
The functions date_create_from_format and date_format correspond to DateTime::createFromFormat and DateTime::format , respectively.
To turn this 20181107 into this 2018-11-07
$str="20181107";
$data = date("Y-m-d", strtotime($str));
strtotime - Interprets any date / time description in English text in Unix timestamp
Date format that the strtotime () interpreter understands: ISO8601% 20181107
See more formats in Date Formats that the strtotime (), DateTime, and date_create () understand