Good morning,
I need to create a csv file listing only name and date of the files within a given directory, but I could not identify any options of the command dir where I bring only those items, most of them have a header and the size of the files.
I'm using it like this
dir "\diretorio_origem\*.pdf" > \diretorio_destino\lista_arquivos.csv
Thank you!
The command would have to be a dir + a double for :
Direct from the command line:
type nul > \diretorio_destino\lista_arquivos.csv && for /f "tokens=* delims=^ " %a in ('dir /a-h-s-d /c /o-n /b "\diretorio_origem\*.pdf"') do for /f "tokens=1,3 delims= " %A in ('@echo/%~ta %~na') do @echo/%B;%~nxA>>.\diretorio_destino\lista_arquivos.csv
Inside a bat file:
@echo off
type nul > \diretorio_destino\lista_arquivos.csv
for /f "tokens=* delims=^ " %%a in ('dir /a-h-s-d /c /o-n /b "\diretorio_origem\*.pdf"') do for /f "tokens=1,3 delims= " %%A in ('echo/%%~ta %%~fa') do echo/%%B;%%~nA>>.\diretorio_destino\lista_arquivos.csv
I understand that the name is extension , if you want the extension strong> ~nA with nxA .